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Completing the Square: Why the Half-Coefficient Rule Works

Rewrite a quadratic in completed-square form and understand the half-the-coefficient rule instead of memorising it blindly.

What you are trying to create

Completing the square rewrites x² + bx + c as (x + p)² + q. This can make turning points, minimum values and equation solving easier to see.

Where the “halve it” rule actually comes from

Expand (x+p)² and you get x² + 2px + p². To match an x-coefficient of b, you need 2p=b, so p=b/2.

Worked example

Rewrite: x² + 6x + 5.
  1. Half 6 to get 3.
  2. Start with (x+3)².
  3. Expanding that gives x²+6x+9, which is 4 too large.
  4. Subtract 4.
x² + 6x + 5 = (x + 3)² − 4

Negative middle term

For x² − 8x + 1, half of −8 is −4:

x² − 8x + 1 = (x − 4)² − 15

If x² has a coefficient

Factor it from the x² and x terms first. For 2x²+8x+1:

2(x² + 4x) + 1 = 2[(x+2)² − 4] + 1 = 2(x+2)² − 7

Expand it once to catch a sign error

Expanding your final form should return the original quadratic exactly. This is the fastest self-check.

Try one yourself

In x² + 10x + 7 = (x + 5)² + q, what is q?

Keep going

For another problem using related ideas, return to the Algebra & Equations page.